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Brian Silverman72890c22015-09-19 14:37:37 -04001MatrixXf matA(2,2), matB(2,2);
2matA << 2, 0, 0, 2;
3
4// Simple but not quite as efficient
5matB = matA * matA;
6cout << matB << endl << endl;
7
8// More complicated but also more efficient
9matB.noalias() = matA * matA;
10cout << matB;