| /* mpz_lucnum_ui -- calculate Lucas number. |
| |
| Copyright 2001, 2003, 2005, 2011, 2012, 2015, 2016 Free Software Foundation, Inc. |
| |
| This file is part of the GNU MP Library. |
| |
| The GNU MP Library is free software; you can redistribute it and/or modify |
| it under the terms of either: |
| |
| * the GNU Lesser General Public License as published by the Free |
| Software Foundation; either version 3 of the License, or (at your |
| option) any later version. |
| |
| or |
| |
| * the GNU General Public License as published by the Free Software |
| Foundation; either version 2 of the License, or (at your option) any |
| later version. |
| |
| or both in parallel, as here. |
| |
| The GNU MP Library is distributed in the hope that it will be useful, but |
| WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY |
| or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License |
| for more details. |
| |
| You should have received copies of the GNU General Public License and the |
| GNU Lesser General Public License along with the GNU MP Library. If not, |
| see https://www.gnu.org/licenses/. */ |
| |
| #include <stdio.h> |
| #include "gmp-impl.h" |
| |
| |
| /* change this to "#define TRACE(x) x" for diagnostics */ |
| #define TRACE(x) |
| |
| |
| /* Notes: |
| |
| For the +4 in L[2k+1] when k is even, all L[4m+3] == 4, 5 or 7 mod 8, so |
| there can't be an overflow applying +4 to just the low limb (since that |
| would leave 0, 1, 2 or 3 mod 8). |
| |
| For the -4 in L[2k+1] when k is even, it seems (no proof) that |
| L[3*2^(b-2)-3] == -4 mod 2^b, so for instance with a 32-bit limb |
| L[0xBFFFFFFD] == 0xFFFFFFFC mod 2^32, and this implies a borrow from the |
| low limb. Obviously L[0xBFFFFFFD] is a huge number, but it's at least |
| conceivable to calculate it, so it probably should be handled. |
| |
| For the -2 in L[2k] with k even, it seems (no proof) L[2^(b-1)] == -1 mod |
| 2^b, so for instance in 32-bits L[0x80000000] has a low limb of |
| 0xFFFFFFFF so there would have been a borrow. Again L[0x80000000] is |
| obviously huge, but probably should be made to work. */ |
| |
| void |
| mpz_lucnum_ui (mpz_ptr ln, unsigned long n) |
| { |
| mp_size_t lalloc, xalloc, lsize, xsize; |
| mp_ptr lp, xp; |
| mp_limb_t c; |
| int zeros; |
| TMP_DECL; |
| |
| TRACE (printf ("mpn_lucnum_ui n=%lu\n", n)); |
| |
| if (n <= FIB_TABLE_LUCNUM_LIMIT) |
| { |
| /* L[n] = F[n] + 2F[n-1] */ |
| MPZ_NEWALLOC (ln, 1)[0] = FIB_TABLE(n) + 2 * FIB_TABLE ((int) n - 1); |
| SIZ(ln) = 1; |
| return; |
| } |
| |
| /* +1 since L[n]=F[n]+2F[n-1] might be 1 limb bigger than F[n], further +1 |
| since square or mul used below might need an extra limb over the true |
| size */ |
| lalloc = MPN_FIB2_SIZE (n) + 2; |
| lp = MPZ_NEWALLOC (ln, lalloc); |
| |
| TMP_MARK; |
| xalloc = lalloc; |
| xp = TMP_ALLOC_LIMBS (xalloc); |
| |
| /* Strip trailing zeros from n, until either an odd number is reached |
| where the L[2k+1] formula can be used, or until n fits within the |
| FIB_TABLE data. The table is preferred of course. */ |
| zeros = 0; |
| for (;;) |
| { |
| if (n & 1) |
| { |
| /* L[2k+1] = 5*F[k-1]*(2*F[k]+F[k-1]) - 4*(-1)^k */ |
| |
| mp_size_t yalloc, ysize; |
| mp_ptr yp; |
| |
| TRACE (printf (" initial odd n=%lu\n", n)); |
| |
| yalloc = MPN_FIB2_SIZE (n/2); |
| yp = TMP_ALLOC_LIMBS (yalloc); |
| ASSERT (xalloc >= yalloc); |
| |
| xsize = mpn_fib2_ui (xp, yp, n/2); |
| |
| /* possible high zero on F[k-1] */ |
| ysize = xsize; |
| ysize -= (yp[ysize-1] == 0); |
| ASSERT (yp[ysize-1] != 0); |
| |
| /* xp = 2*F[k] + F[k-1] */ |
| #if HAVE_NATIVE_mpn_addlsh1_n |
| c = mpn_addlsh1_n (xp, yp, xp, xsize); |
| #else |
| c = mpn_lshift (xp, xp, xsize, 1); |
| c += mpn_add_n (xp, xp, yp, xsize); |
| #endif |
| ASSERT (xalloc >= xsize+1); |
| xp[xsize] = c; |
| xsize += (c != 0); |
| ASSERT (xp[xsize-1] != 0); |
| |
| ASSERT (lalloc >= xsize + ysize); |
| c = mpn_mul (lp, xp, xsize, yp, ysize); |
| lsize = xsize + ysize; |
| lsize -= (c == 0); |
| |
| /* lp = 5*lp */ |
| #if HAVE_NATIVE_mpn_addlsh2_n |
| c = mpn_addlsh2_n (lp, lp, lp, lsize); |
| #else |
| /* FIXME: Is this faster than mpn_mul_1 ? */ |
| c = mpn_lshift (xp, lp, lsize, 2); |
| c += mpn_add_n (lp, lp, xp, lsize); |
| #endif |
| ASSERT (lalloc >= lsize+1); |
| lp[lsize] = c; |
| lsize += (c != 0); |
| |
| /* lp = lp - 4*(-1)^k */ |
| if (n & 2) |
| { |
| /* no overflow, see comments above */ |
| ASSERT (lp[0] <= MP_LIMB_T_MAX-4); |
| lp[0] += 4; |
| } |
| else |
| { |
| /* won't go negative */ |
| MPN_DECR_U (lp, lsize, CNST_LIMB(4)); |
| } |
| |
| TRACE (mpn_trace (" l",lp, lsize)); |
| break; |
| } |
| |
| MP_PTR_SWAP (xp, lp); /* balance the swaps wanted in the L[2k] below */ |
| zeros++; |
| n /= 2; |
| |
| if (n <= FIB_TABLE_LUCNUM_LIMIT) |
| { |
| /* L[n] = F[n] + 2F[n-1] */ |
| lp[0] = FIB_TABLE (n) + 2 * FIB_TABLE ((int) n - 1); |
| lsize = 1; |
| |
| TRACE (printf (" initial small n=%lu\n", n); |
| mpn_trace (" l",lp, lsize)); |
| break; |
| } |
| } |
| |
| for ( ; zeros != 0; zeros--) |
| { |
| /* L[2k] = L[k]^2 + 2*(-1)^k */ |
| |
| TRACE (printf (" zeros=%d\n", zeros)); |
| |
| ASSERT (xalloc >= 2*lsize); |
| mpn_sqr (xp, lp, lsize); |
| lsize *= 2; |
| lsize -= (xp[lsize-1] == 0); |
| |
| /* First time around the loop k==n determines (-1)^k, after that k is |
| always even and we set n=0 to indicate that. */ |
| if (n & 1) |
| { |
| /* L[n]^2 == 0 or 1 mod 4, like all squares, so +2 gives no carry */ |
| ASSERT (xp[0] <= MP_LIMB_T_MAX-2); |
| xp[0] += 2; |
| n = 0; |
| } |
| else |
| { |
| /* won't go negative */ |
| MPN_DECR_U (xp, lsize, CNST_LIMB(2)); |
| } |
| |
| MP_PTR_SWAP (xp, lp); |
| ASSERT (lp[lsize-1] != 0); |
| } |
| |
| /* should end up in the right spot after all the xp/lp swaps */ |
| ASSERT (lp == PTR(ln)); |
| SIZ(ln) = lsize; |
| |
| TMP_FREE; |
| } |